Pascal's Identity is a combinatorial identity about binomial coefficients:
or ![]()
We can prove the equation by expanding the formula for
choose
and
choose
:
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Let’s consider the intuition behind the equation. The left-hand
side chooses a subset of
items from
items.
There are two possible cases:
·
The first item is not chosen: We need to choose
items
from the remaining
items, which has
combinations.
·
The first item is chosen: We need to choose
items
from the remaining
items, which has
combinations.
The total number of combinations is
and ![]()
Figure 3‑12 shows Pascal’s Triangle. The elements
on the left and the right edges of the Pascal’s Triangle are
. The
rest of the elements are calculated using the same rule: each element is the
sum of the two elements above it. For example, the 3rd element in line 4 is the
sum of the 2nd element in line 3 and the 3rd element in line 3: ![]()

Figure 3‑12 Pascal’s Triangle
As shown in Figure 3‑13, the k-th element in line
n of the Pascal’s Triangle, where
is the number of
combinations of n distinct items taken
at a
time,
This is the result of
how each element is calculated: When
or
its
value is
When
is
between 1 and n, it is the sum of the two elements above the k-th
element in line n,
and
Using Pascal’s Identity,
we get the k-th element in line n as ![]()

Figure 3‑13 Elements in Pascal’s Triangle
Problem 3‑28
Prove the Hockey Stick Identity: ![]()
Solution:
The key to the proof is to recognize
. Once we replace the
first term on the right-hand side as
we can repeatedly apply
Pascal’s Identity:
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